16x^2+8x=120

Solution for 16x^2+8x=120 equation:

16x^2+8x=120

We move all terms to the left:

16x^2+8x-(120)=0

a = 16; b = 8; c = -120;
Δ = b2-4ac
Δ = 82-4·16·(-120)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*16}=\frac{80}{32}
=2+1/2
$